23=2*(8x^3/4)^2/3-17

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Solution for 23=2*(8x^3/4)^2/3-17 equation: 


x in (-oo:+oo)

23 = (2*((8*x^3)/4)^2)/3-17 // - (2*((8*x^3)/4)^2)/3-17

17-((2*((8*x^3)/4)^2)/3)+23 = 0

(-2/3)*((8*x^3)/4)^2+17+23 = 0

-8/3*x^6 = -40 // : -8/3

x^6 = 15

x^6 = 15 // ^ 1/6

abs(x) = 15^(1/6)

x = 15^(1/6) or x = -15^(1/6)

x in { 15^(1/6), -15^(1/6) }

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